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05-02-2021, 01:13 PM | #1 | |||
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You know my methods
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SO we are drawing lines on xy axis using standard equations (simultaneous equation homework) and we have done all the standard 3x +5y=15 type ones but the last one is 4y=3x
wtf that is 2 variables but what is the number? do i move 3x to the right to get like -3x +4y=1? |
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05-02-2021, 01:22 PM | #2 | |||
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Skinny Legend
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Yeah
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The scars on my mind are on replay |
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05-02-2021, 01:24 PM | #3 | |||
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You know my methods
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you dont know
i need smarts |
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05-02-2021, 01:26 PM | #4 | |||
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Oh no, I'm English
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Jake is the maths genius on here.
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Last edited by The Slim Reaper; 05-02-2021 at 01:27 PM. |
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05-02-2021, 01:29 PM | #5 | |||
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I Love my brick
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I hate Maths sorry
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Spoiler: |
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05-02-2021, 01:41 PM | #6 | |||
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Senior Member
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Quote:
If you imagine, say, y=3 and x=4. Last edited by James; 05-02-2021 at 01:41 PM. |
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05-02-2021, 01:41 PM | #7 | |||
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Senior Member
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05-02-2021, 01:44 PM | #8 | |||
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This Witch doesn't burn
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Alegebra
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'put a bit of lippy on and run a brush through your hair, we are alcoholics, not savages' |
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05-02-2021, 01:54 PM | #9 | |||
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Who, Douglas?
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Quote:
So you could divide by 3x, meaning it’d be 4Y/3x =1 in order to get a number Subtracting would just make it equal 0 rather than 1 LT, so I guess you could do -3x +4Y= 0 also You can then use the other simultaneous equation to get either the x or y and work out the remaining one by plugging in the number
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Douglas’s Love Island season 5 least faves: Yewande, Anna, Jourdan, Joanna and Lavena New Love Island least faves: Kaz, Tyler, Faye, Sharon, Rachel Sig images and links removed for rule breaking - TiBB Staff Last edited by DouglasS; 05-02-2021 at 01:56 PM. |
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05-02-2021, 03:20 PM | #10 | |||
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You know my methods
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05-02-2021, 03:26 PM | #11 | |||
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Senior Member
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Quote:
It’s been a while since I did simultaneous equations so I’m a little rusty but my answer’s 2.2 for x and 1.7 for y.
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05-02-2021, 03:39 PM | #12 | |||
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Senior Member
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You said these equations were supposed to be solved via line graphs but here’s the working out:
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Don’t let your regret be stronger than your gratitude. And don’t hang on to negativity. That’s all. |
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06-02-2021, 12:27 AM | #13 | |||
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Senior Member
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Wow now I have a sore head
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06-02-2021, 10:12 AM | #14 | ||
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As simply as I can phrase it - you solve one of the equations for X and then sub in what you get so that the 2nd equation only has Y values.
In this case, I actually think starting with the 2nd equation is easier; 4y = 3x 3x = 4y (3x/3) = (4y/3) x = (4y/3) Thus 3x+5y=15 3(4y/3)+5y=15 [no more X, yay] multiply out the bracket, first by multiplying both sides by 3: 3(4y)+15y=45 then simplifying the left hand side 12y+15y=45 27y = 45 y=45/27 find lowest terms y = 5/3 (approx 1.67) Then solve X using what you got earlier x = 4y/3 x = 4(5/3)/3 (you can multiply all of this out on paper but just use a damn calculator ) x = 20/9 (approx 2.22) I think I made it seem more complicated than it is though. tl;dr you solve one as far as you can to eliminate a variable from the other. It doesn't matter which. Last edited by Toy Soldier; 06-02-2021 at 10:13 AM. |
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06-02-2021, 10:12 AM | #15 | |||
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Skinny Legend
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Yeah
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The scars on my mind are on replay |
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